Determine whether this proposition is a tautology.
[(p → q) Ù (q → r)] → (p→ r)
Let p=1,q=0,r=0. Then
"p\\rightarrow q=0\\\\\np\\rightarrow q=0\\\\\nq\\rightarrow r=1\\\\\n(p\\rightarrow q)\\lor (q\\rightarrow r)=1\\\\\n((p\\rightarrow q)\\lor (q\\rightarrow r))\\rightarrow (p\\rightarrow r)=0"
The formula is not a tautology.
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