show that ~p --> (q --> r ) and q --> (p v r) are logically equivalent
"\\lnot p\\rightarrow \\left( q\\rightarrow r \\right) =p\\lor \\left( q\\rightarrow r \\right) =p\\lor \\left( \\lnot q\\lor r \\right) =p\\lor \\lnot q\\lor r\\\\q\\rightarrow \\left( p\\lor r \\right) =\\lnot q\\lor \\left( p\\lor r \\right) =p\\lor \\lnot q\\lor r"
We obtain the same expressions, thus the formulae are logically equivalent.
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