Convert the following formula to conjunctive normal form: A ⇒ ( B ∧ C )
A. ( ¬A ∨ B ) ∧ ( ¬A ∨ C )
B. ( A ∧ ¬B ) ∨ ( A ∧ ¬C )
C. ( ¬A ∧ B ) ∨ ( ¬A ∧ C )
D. ( A ∨ ¬B ) ∧ ( A ∨
A is correct:A→(B∧C)=¬A∨(B∧C)==(¬A∨B)∧(¬A∨C)A\,\,is\,\,correct:\\A\rightarrow \left( B\land C \right) =\lnot A\lor \left( B\land C \right) =\\=\left( \lnot A\lor B \right) \land \left( \lnot A\lor C \right)Aiscorrect:A→(B∧C)=¬A∨(B∧C)==(¬A∨B)∧(¬A∨C)
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