Convert the following formula to conjunctive normal form: A ⇒ ( B ∧ C )
A. ( ¬A ∨ B ) ∧ ( ¬A ∨ C )
B. ( A ∧ ¬B ) ∨ ( A ∧ ¬C )
C. ( ¬A ∧ B ) ∨ ( ¬A ∧ C )
D. ( A ∨ ¬B ) ∧ ( A ∨
"A\\,\\,is\\,\\,correct:\\\\A\\rightarrow \\left( B\\land C \\right) =\\lnot A\\lor \\left( B\\land C \\right) =\\\\=\\left( \\lnot A\\lor B \\right) \\land \\left( \\lnot A\\lor C \\right)"
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