[¬p ∧(p ∨ q)]→q
Solution
To prove
[¬p∧(p∨q)]→q[¬p ∧(p ∨ q)]→q[¬p∧(p∨q)]→q
¬[¬p∧(p∨q)]∨q¬[¬p ∧ (p ∨ q)] ∨ q¬[¬p∧(p∨q)]∨q
(¬¬p∨¬(p∨q))∨q(¬¬p ∨ ¬(p ∨ q)) ∨ q(¬¬p∨¬(p∨q))∨q
p∨(¬p∧¬q))∨qp ∨ (¬p ∧ ¬q)) ∨ qp∨(¬p∧¬q))∨q
((p∨¬p)∧(p∨¬q))∨q((p ∨ ¬p) ∧ (p ∨ ¬q)) ∨ q((p∨¬p)∧(p∨¬q))∨q
(T∧(p∨¬q))∨q(T ∧ (p ∨ ¬q)) ∨ q(T∧(p∨¬q))∨q
(p∨¬q)∨q(p ∨ ¬q) ∨ q(p∨¬q)∨q
p∨(¬q∨q)p ∨ (¬q ∨ q)p∨(¬q∨q)
p∨Tp ∨ Tp∨T
TTT
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