Question #301935

6. Team A has probability 2/3 of winning whenever it plays.suppose A plays four Games.find the probability p that A wins more than half of its gamed.


Expert's answer

Let X=X= the number of games won: X∼Bin(n,p).X\sim Bin (n, p).

Given p=2/3,n=4,q=1−p=1/3.p=2/3, n=4, q=1-p=1/3.


P(X≥3)=P(X=3)+P(X=4)P(X\ge3)=P(X=3)+P(X=4)

=(43)(23)3(13)+(44)(23)4=1627=\dbinom{4}{3}(\dfrac{2}{3})^3(\dfrac{1}{3})+\dbinom{4}{4}(\dfrac{2}{3})^4=\dfrac{16}{27}


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