Construct the truth table of the following proposition.
1. (p∧q)→(p∨q)
2. ~(p→q)
3. (p∨q)∧~p
Let us construct the truth table of the following proposition.
1. "(p\u2227q)\u2192(p\u2228q)"
"\\begin{array}{||c|c||c|c|c||}\n\\hline\\hline\np & q & p\u2227q & p\u2228q & (p\u2227q)\u2192(p\u2228q)\\\\\n\\hline\\hline\n0 & 0 & 0 & 0 & 1\\\\\n\\hline\n0 & 1 & 0 & 1 & 1\\\\\n\\hline\n1 & 0 & 0 & 1 & 1\\\\\n\\hline \n1 & 1 & 1 & 1 & 1\\\\\n\\hline\\hline\n\\end{array}"
2. "\\sim(p\u2192q)"
"\\begin{array}{||c|c||c|c|c||}\n\\hline\\hline\np & q & p\u2192q & \\sim(p\u2192q) \\\\\n\\hline\\hline\n0 & 0 & 1 & 0 \\\\\n\\hline\n0 & 1 & 1 & 0 \\\\\n\\hline\n1 & 0 & 0 & 1 \\\\\n\\hline \n1 & 1 & 1 & 0 \\\\\n\\hline\\hline\n\\end{array}"
3. "(p\u2228q)\u2227\\sim p"
"\\begin{array}{||c|c||c|c|c||}\n\\hline\\hline\np & q & \\sim p & p\u2228q & (p\u2228q)\u2227\\sim p\\\\\n\\hline\\hline\n0 & 0 & 1 & 0 & 0\\\\\n\\hline\n0 & 1 & 1 & 1 & 1\\\\\n\\hline\n1 & 0 & 0 & 1 & 0\\\\\n\\hline \n1 & 1 & 0 & 1 & 0\\\\\n\\hline\\hline\n\\end{array}"
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