Determine the truth value of the following statement.
(∃n ∈Z)(n2= 3)
(∃n∈Z)(n2=3)⇒n2=3⇒n=±3∉Z(∃n ∈Z)(n^2= 3) \\\Rightarrow n^2=3 \\\Rightarrow n=\pm \sqrt 3 \notin Z(∃n∈Z)(n2=3)⇒n2=3⇒n=±3∈/Z
But given is n∈Zn \in Zn∈Z.
Thus, it is false.
Truth value is F.
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