[T] Find Q∪N\mathbb{Q}\cup \mathbb{N}Q∪N ?
N={0,1,2,3,…},\N = \{0, 1, 2, 3, …\},N={0,1,2,3,…}, the set of all natural numbers.
Q={p∕q∣p∈Z,q∈Z,and q≠0}Q= \{p∕q ∣ p ∈ \Z, q ∈ \Z, and \ q\not=0\}Q={p∕q∣p∈Z,q∈Z,and q=0} and q ≠ 0}, the set of all rational numbers.
Then
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