Answer to Question #281728 in Discrete Mathematics for Neha

Question

There are 10 stalls for animals in an exhibition. Three animals; lion, pussycat

and horse are to be exhibited. Animals of each kind are not less than 10 in

number. What is the possible number of ways of arranging the exhibition?

Answer 1

Total number of stalls for animals in exhibition = 10

Number of each of three type animal = at least 10

Types of animals = 3 (animals; lion, pussycat)

Then, possible number of ways of arranging the exhibition are:

$3^{10}=3\times3\times3\times3\times3\times3\times3\times3\times3\times3=59049$

There are total 59049 ways to fill the 10 stalls in exhibition.