Suppose we are given a Boolean function f(x, y, z)=(x+y)(x+y)(x+2). Find its DN form
A logical formula is considered to be in DNF if it is a disjunction of one or more conjunctions of one or more literals.
f(x,y,z)=(x+y)(x+y)(x+2)=(x+xy+y)(x+2)=f(x, y, z)=(x+y)(x+y)(x+2)=(x+xy+y)(x+2)=f(x,y,z)=(x+y)(x+y)(x+2)=(x+xy+y)(x+2)=
=x+2x+xy+xy+xy+2y=x+xy+y=x∨(x∧y)∨y=x+2x+xy+xy+xy+2y=x+xy+y=x\lor (x\land y)\lor y=x+2x+xy+xy+xy+2y=x+xy+y=x∨(x∧y)∨y
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