Consider the recurrence relation an= 3 an1 + 3 an-2 when ao = 1 and a1= 2 then a3= ..: O 56
an=3an−1+3an−2a_n= 3 a_{n-1} + 3 a_{n-2}an=3an−1+3an−2
a2=3a1+3a0=6+3=9a_2=3a_1+3a_0=6+3=9a2=3a1+3a0=6+3=9
a3=3a2+3a1=3⋅9+3⋅2=33a_3=3a_2+3a_1=3\cdot9+3\cdot2=33a3=3a2+3a1=3⋅9+3⋅2=33
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment