Question #277054

3Fn − Fn−2 = Fn+2, for n ≥ 3.


1
Expert's answer
2021-12-08T12:59:14-0500

The sequence of Fibonacci numbers, F0,F1,F2,F3,...,F_0, F_1, F_2,F_3, . . ., are defined by the following equations: 


F0=0,F_0=0,F1=1,F_1=1,Fn=Fn1+Fn2,n2F_n=F_{n-1}+F_{n-2}, n\geq 2

Then for n3n\geq 3

Fn+2=Fn+1+Fn=Fn+Fn1+FnF_{n+2}=F_{n+1}+F_n=F_n+F_{n-1}+F_n

=2Fn+FnFn2=3FnFn2=2F_n+F_n-F_{n-2}=3F_n-F_{n-2}

Therefore


3FnFn2=Fn+2,n33F_n-F_{n-2}=F_{n+2}, n\geq 3


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