How many ways are there to select 12 countries in the United Nations to serve on a council if 3 is selected from a block of 53, 1 are selected from a block of 62 and 8 are selected from the remaining 74 countries?
By combinatorial product principle, the number of ways is equal to
"C_{53}^3\\cdot C_{62}^1\\cdot C_{74}^8\n=\\frac{53\\cdot 52\\cdot 51}{2\\cdot 3}\\cdot62\\cdot \\frac{74\\cdot 73\\cdot 72\\cdot 71\\cdot 70\\cdot 69\\cdot 68\\cdot 67}{2\\cdot 3\\cdot 4\\cdot 5\\cdot 6\\cdot 7\\cdot 8}\\approx 2.189\\cdot 10^{16}."
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