Let f(x) = x – 3 , g(x) = 2x + 1 and h(x) = x2 – 5. Find the following 1. f ₒ g 2. f ₒ h 3. h ₒ g 4. g ₒ f 5. g ₒ h
1.
f∘g=2x+1−3=2x−2f\circ g=2x+1-3=2x-2f∘g=2x+1−3=2x−2
2.
f∘h=x2−5−3=x2−8f\circ h=x^2-5-3=x^2-8f∘h=x2−5−3=x2−8
3.
h∘g=(2x+1)2−5=4x2+4x−4h\circ g=(2x+1)^2-5=4x^2+4x-4h∘g=(2x+1)2−5=4x2+4x−4
4.
g∘f=2(x−3)+1=2x−5g\circ f=2(x-3)+1=2x-5g∘f=2(x−3)+1=2x−5
5.
g∘h=2(x2−5)+1=2x2−9g\circ h=2(x^2-5)+1=2x^2-9g∘h=2(x2−5)+1=2x2−9
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