1. Find a relation R such that 𝑥+𝑦 2 >1 if A = {0,1, 2} and B ={0, 1, 2, 3}.
Let us find a relation R⊂A×BR\subset A\times BR⊂A×B such that (x,y)∈R(x,y)\in R(x,y)∈R iff 𝑥+𝑦2>1𝑥+𝑦^2 >1x+y2>1 if A={0,1,2}A =\{0,1, 2\}A={0,1,2} and B={0,1,2,3}.B =\{0, 1, 2, 3\}.B={0,1,2,3}.
It follows that
R={(0,2),(0,3),(1,1),(1,2),(1,3),R=\{(0,2),(0,3),(1,1),(1,2),(1,3),R={(0,2),(0,3),(1,1),(1,2),(1,3),
(2,0),(2,1),(2,2),(2,3)}.(2,0),(2,1),(2,2),(2,3)\}.(2,0),(2,1),(2,2),(2,3)}.
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