What is the truth value of ∀xP(x), where P(x) is the statement “x2 < 10” and the domain consists
of the positive integers not exceeding 4?
x2<10 ⟹ x∈(−10,10)x^2<10\implies x\in (-\sqrt{10},\sqrt{10})x2<10⟹x∈(−10,10). 4>104>\sqrt{10}4>10 , so, P(4) = 0, so, the given statement is false
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