Question #273974

Show that the relation R = ∅ on the empty set S = ∅ is


reflexive, symmetric, and transitive.

Expert's answer

A binary relation RR is called reflexive if (a,a)∈R(a,a)\in R for any a∈S.a\in S. Since S=∅S=\emptyset, it contains no elements. Therefore, the statement "a∈∅=Sa\in \emptyset=S" is false. Consequently, the implication "if a∈Sa\in S then (a,a)∈R(a,a)\in R" is true for any a∈S.a\in S. It follows that R=∅R=\emptyset is reflexive relation on the set S=∅S=\emptyset.


A binary relation RR on a set SS is called symmetric if (a,b)∈R(a,b)\in R implies (b,a)∈R(b,a)\in R. Taking into account that R=∅R=\emptyset, we conclude that the statement "(a,b)∈R(a,b)\in R" is false. Therefore, the implication "if (a,b)∈R(a,b)\in R then (b,a)∈R(b,a)\in R" is true. So, the relation R=∅R=\emptyset is symmetric.


A binary relation RR on a set SS is called transitive if (a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R implies (a,c)∈R(a,c)\in R. Taking into account that R=∅R=\emptyset, we conclude that the statement "(a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R" is false. Therefore, the implication "if (a,b)∈R(a,b)\in R and (b,c)∈R(b,c)\in R then (a,c)∈R(a,c)\in R" is true. So, the relation R=∅R=\emptyset is transitive.


LATEST TUTORIALS
APPROVED BY CLIENTS