Question #27081

Problem 4
Determine |A ∪ B ∪ C| when |A|= 50, |B|= 500, and
|C| 5000, if (a)A ⊆ B ⊆ C; (b)A ∩ B A ∩ C B ∩ C
∅; and (c) |A ∩ B| |A ∩ C| |B ∩ C| 3 and |A ∩ B ∩ C| 1.

Expert's answer

Question 1. Determine ABC|A \cup B \cup C| when A=50|A| = 50, B=500|B| = 500 and C=5000|C| = 5000, if

(a) ABCA \subseteq B \subseteq C;

(b) AB=AC=BC=A \cap B = A \cap C = B \cap C = \emptyset;

(c) AB=AC=BC=3|A \cap B| = |A \cap C| = |B \cap C| = 3 and ABC=1|A \cap B \cap C| = 1.

Solution. (a) If ABCA \subseteq B \subseteq C, then ABC=CA \cup B \cup C = C, so ABC=C=5000|A \cup B \cup C| = |C| = 5000.

(b) If AB=AC=BC=A \cap B = A \cap C = B \cap C = \emptyset, then ABC=A+B+C=50+500+5000=5550|A \cup B \cup C| = |A| + |B| + |C| = 50 + 500 + 5000 = 5550.

(c) Now if AB=AC=BC=3|A \cap B| = |A \cap C| = |B \cap C| = 3 and ABC=1|A \cap B \cap C| = 1, then by inclusion-exclusion formula


ABC=A+B+CABACBC+ABC=50+500+5000333+1=5542.\begin{array}{l} |A \cup B \cup C| = |A| + |B| + |C| - |A \cap B| - |A \cap C| - |B \cap C| + |A \cap B \cap C| \\ = 50 + 500 + 5000 - 3 - 3 - 3 + 1 \\ = 5542. \end{array}


Answer:

(a) 5000;

(b) 5550;

(c) 5542.


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