Consider the sets A and B, where A = {3, |B|} and B = {1, |A|, |B|}.
Let us prove by contradiction that Suppose that |B| = 3. Then cardinality of the set A = {3, 3} = {3} is equal to 1, and hence the set B = {1, |A|, |B|} = {1, 1, 3} = {1, 3} has cardilality 2. And we have a contradiction with |B| = 3.
Therefore, and hence It follows that Then and hence
We conclude that and
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