Question #260584

Consider the sets A and B, where A = {3, |B|} and B = {1, |A|, |B|}. What are the sets?

1
Expert's answer
2021-11-03T18:20:09-0400

Consider the sets A and B, where A = {3, |B|} and B = {1, |A|, |B|}. 

Let us prove by contradiction that B3.|B|\ne 3. Suppose that |B| = 3. Then cardinality of the set A = {3, 3} = {3} is equal to 1, and hence the set B = {1, |A|, |B|} = {1, 1, 3} = {1, 3} has cardilality 2. And we have a contradiction with |B| = 3.

Therefore, B3,|B|\ne 3, and hence B<3.|B|<3. It follows that A=2.|A|=2. Then B={1,A,B}={1,2,B},B = \{1, |A|, |B|\}=\{1, 2,|B|\}, and hence B=2.|B|=2.

We conclude that A={3,2}A=\{3,2\} and B={1,2}.B=\{1,2\}.



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