Answer to Question #259040 in Discrete Mathematics for htd

Question #259040

For each relation below, determine if they are reflexive, symmetric, anti-symmetric, and transitive.


(a) X= { 1, 2, 3, 4}

R1={(1, 2),(2, 3),(3, 4)}


(b) X = {a, b, c, d, e}

R1 = { (a, a), (a, b), (a, e), (b, b), (b, e), (c, c), (c, d), (d, d), (e, e) }


(c) X= { 1, 2, 3, 4}

R1= {(1, 3),(1, 4),(2, 3),(2, 4),(3, 1),(3, 4)}


1
Expert's answer
2021-11-02T12:30:41-0400

A relation "R" on a set "A" is called reflexive if "(a, a) \u2208 R" for every element "a \u2208 A."


A relation "R" on a set "A" is called symmetric if "(b, a) \u2208 R" whenever "(a, b) \u2208 R," for all "a, b \u2208 A."


A relation "R" on a set "A" such that for all "a, b \u2208 A," if "(a, b) \u2208 R" and "(b, a) \u2208 R," then "a = b" is

called antisymmetric.


A relation "R" on a set "A" is called transitive if whenever "(a, b) \u2208 R" and "(b, c) \u2208 R," then "(a, c) \u2208 R," for all "a, b, c \u2208 A."



(a)

"X= \\{ 1, 2, 3, 4\\}"

"R1=\\{(1, 2),(2, 3),(3, 4)\\}"

Not reflexive because we do not have "(1, 1),(2,2), (3, 3)," and "(4, 4)."

Not symmetric because while we have "(1, 2)," we do not have "(2, 1)."

Antisymmetric.

Not transitive because we do not have "(1, 3)" for "(1, 2)" and "(2, 3)."  


(b)

"X= \\{ a, b, c, d, e\\}"

"R1=\\{(a, a), (a, b), (a, e), (b, b), (b, e), (c, c), (c, d),"

"(d, d), (e, e) \\}"

Reflexive because we have "(a, a), (b, b),(c, c), (d, d)," and "(e,e)."

Not symmetric because while we have "(a, b)," we do not have "(b, a)."

Antisymmetric.

Transitive.  


(c)

"X= \\{ 1, 2, 3, 4\\}"

"R1=\\{(1, 3),(1, 4),(2, 3),(2, 4),(3, 1),(3, 4)\\}"

Not reflexive because we do not have "(1, 1),(2,2), (3, 3)," and "(4, 4)."

Not symmetric because while we have "(1, 4)," we do not have "(4, 1)."

Not antisymmetric because we have both "(1,3)" and "(3, 1)."

Not transitive because we do not have "(1, 1)" for "(1, 3)" and "(3, 1)."  



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