Given that n is a positive integer and in the expansion of (1+ax)n, the coefficient of x is 200. Find the coefficient of x in the expansion of (1+ax)2n.
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Expert's answer
2021-10-27T15:25:04-0400
(1+ax)n:
(1n)(ax)(1)n−1=nax=200x
na=200
(1+ax)2n:
(12n)(ax)(1)2n−1=2nax=2(200)x=400x
The coefficient of x in the expansion of (1+ax)2n is 400.
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