Question #257331

Given that n is a positive integer and in the expansion of (1+ax)n, the coefficient of x is 200. Find the coefficient of x in the expansion of (1+ax)2n.


1
Expert's answer
2021-10-27T15:25:04-0400

(1+ax)n:(1+ax)^n:


(n1)(ax)(1)n1=nax=200x\dbinom{n}{1}(ax)(1)^{n-1}=nax=200x

na=200na=200

(1+ax)2n:(1+ax)^{2n}:


(2n1)(ax)(1)2n1=2nax=2(200)x=400x\dbinom{2n}{1}(ax)(1)^{2n-1}=2nax=2(200)x=400x

The coefficient of xx in the expansion of (1+ax)2n(1+ax)^{2n} is 400.400.



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