Let us find ∪i=1∞Ai and ∩i=1∞Ai where Ai={i,i+1,i+2,…} for every positive integer i.
Taking into account that Ai⊃Aj for j>i, we conclude that ∪i=1∞Ai=A1={1,2,3,…}.
Let us show that ∩i=1∞Ai=∅ using the method by contradiction. Suppose that k∈∩i=1∞Ai for some positive integer k. Since k∈/{k+1,k+2,…}=Ak+1, we conclude that k∈/∩i=1∞Ai. This contradiction proves that ∩i=1∞Ai=∅.
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