Let us find āŖi=1āāAiā and ā©i=1āāAiā where Aiā={i,i+1,i+2,ā¦} for every positive integer i.
Taking into account that AiāāAjā for j>i, we conclude that āŖi=1āāAiā=A1ā={1,2,3,ā¦}.
Let us show that ā©i=1āāAiā=ā
using the method by contradiction. Suppose that kāā©i=1āāAiā for some positive integer k. Since kā/{k+1,k+2,ā¦}=Ak+1ā, we conclude that kā/ā©i=1āāAiā. This contradiction proves that ā©i=1āāAiā=ā
.