Find β π¨π β π=π and β π¨π β π=π where:
π¨π = {π,π + π,π + π, β¦ } for every positive integer π.
Let us find "\\cup_{i=1}^{\\infty}A_i" and "\\cap_{i=1}^{\\infty}A_i" where "A_i = \\{i,i+1,i+2, \u2026 \\}" for every positive integer "i".
Taking into account that "A_i\\supset A_j" for "j>i," we conclude that "\\cup_{i=1}^{\\infty}A_i=A_1=\\{1,2,3,\\ldots\\}."
Let us show that "\\cap_{i=1}^{\\infty}A_i=\\emptyset" using the method by contradiction. Suppose that "k\\in \\cap_{i=1}^{\\infty}A_i" for some positive integer "k". Since "k\\notin\\{k+1,k+2,\\ldots\\}=A_{k+1}," we conclude that "k\\notin\\cap_{i=1}^{\\infty}A_i." This contradiction proves that "\\cap_{i=1}^{\\infty}A_i=\\emptyset."
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