Part a
"\\exist x (x^2 =2)\\\\\nHere \\space x= \u2213 \\sqrt{2} \\space \\space so \\space satisfy". Ture
Part b
"\\exist x (x^2 =1)\\\\"
Since for no real number, the square can be negative. So it is false.
Part c
"\\forall x (x^2+2*)"
* These symbols are not proper of the reformulate up to the best of my knowledge "\\forall x (x^2 \\land x \\not= 1)" False
Part d
"\\forall x (x^2+x)"
Since for every real number x2+x has a solution. True
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