Answer to Question #251537 in Discrete Mathematics for Cass

Question #251537

prove that AUB = AU(B\A)

Expert's answer

"A \u222a (B \u2212 A) = A \u222a (B \u2229 A^C)" set difference

"= A \u222a (A^C \u2229 B)" commutative

"= (A \u222a A^C) \u2229 (A \u222a B)" distributive

"= U \u2229 (A \u222a B)" complement

"= A \u222a B" identity

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