Build a complete truth table and Show that they are Logically equivalent
¬(¬P ∧ Q) ∧ (P ∨Q)≡ p
Solution:
LHS=¬(¬P∧Q)∧(P∨Q)=¬(¬P ∧ Q) ∧ (P ∨Q)=¬(¬P∧Q)∧(P∨Q)
Truth table:
RHS=P=P=P
Thus, ¬(¬P∧Q)∧(P∨Q)≡P¬(¬P ∧ Q) ∧ (P ∨Q)≡ P¬(¬P∧Q)∧(P∨Q)≡P are logically equivalent.
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