Question #246294

R3 = {(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),

(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}


  1. Determine whether the relation R3 is reflexive, symmetric, anti-symmetric and transitive.    
  2.  Determine whether the relation R3 is an equivalence relation or partial order. Give reason for your answer                                    
1
Expert's answer
2021-10-04T18:25:50-0400

Consider the relation R3={ (1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4) }R_3 = \{\ (1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4), \\ (3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)\ \}on the set A={1,2,3,4}.A=\{1,2,3,4\}.

  1. Since (a,a)R3(a,a)\in R_3 for each aA,a\in A, the relation R3R_3 is reflexive. Taking into account that (a,b)R3(a,b)\in R_3 implies (b,a)R3(b,a)\in R_3 for any pair (a,b)R3,(a,b)\in R_3, we conclude that the relation R3R_3 is symmetric. Since (1,2)R3(1,2)\in R_3 and (2,1)R3,(2,1)\in R_3, this relation is not anti-symmetric. Taking into account that (a,b)R3(a,b)\in R_3 and (b,c)R3(b,c)\in R_3 implies (a,c)R3(a,c)\in R_3 for any pairs (a,b),(b,c)R3,(a,b),(b,c)\in R_3, we conclude that the relation R3R_3 is transitive.
  2. Since the relation R3R_3 is reflexive, symmetric and transitive, it is an equivalence relation. Taking into account that R3R_3 is not anti-symmetric, we conclude that R3R_3 is not a partial order.

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