Construct a truth table for each of these compound statements.(p↔( p \leftrightarrow(p↔ q) →(¬p↔q)\to(\lnot p \leftrightarrow q )→(¬p↔q)
Let us construct a truth table for the compound statement (p↔( p \leftrightarrow(p↔ q) →(¬p↔q)\to(\lnot p \leftrightarrow q )→(¬p↔q)
pqp↔q¬p¬p↔qp↔q→¬p↔q001100010111100011111000\begin{array}{||c|c|c|c|c|c||} \hline\hline p & q & p\leftrightarrow q & \neg p & \neg p\leftrightarrow q & p\leftrightarrow q \to \neg p\leftrightarrow q\\ \hline\hline 0 & 0 & 1 & 1 & 0 & 0\\ \hline 0 & 1 & 0 & 1 & 1 & 1\\ \hline 1 & 0 & 0 & 0 & 1 & 1\\ \hline 1 & 1 & 1 & 0 & 0 & 0\\ \hline\hline \end{array}p0011q0101p↔q1001¬p1100¬p↔q0110p↔q→¬p↔q0110
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