Answer to Question #235125 in Discrete Mathematics for mickey

Question #235125

Determine whether each of these functions is a bijection from R to R.

f (x) = (x2 + 1)/(x2 + 2)


1
Expert's answer
2021-09-10T12:09:46-0400

f(x)=x2+1x2+2For  x=1=>f(x)=1+11+2=23For  x=1=>f(x)=1+11+2=23f(x) = \frac{x^2+1}{x^2+2} \\ For \; x=-1 => f(x) = \frac{1+1}{1+2}= \frac{2}{3} \\ For\; x=1 => f(x) = \frac{1+1}{1+2}= \frac{2}{3}

=> Not one-to-one function

=> Not a bijective (no inverse exists)


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