Q#: A binary operation ∇ on [0,1] is a t-norm if and only if x∇(y∇z)=(x∇y)∇z
∇ is t-norm <=> x∇(y∇z) =(x∇y)∇z
∇ is t-norm on [0,1]
∇ is associative
x,y,z "\\in" [0,1]
(x∇y)∇z = x∇(y∇z), "\\forall" x,y,z "\\in" [0,1]
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