Question #234691
Determine whether each of these functions is a bijection from R to R.
f (x) = (x2 + 1)/(x2 + 2)
1
Expert's answer
2021-09-09T13:06:01-0400

f(x)=x2+1x2+2f(x) = \frac{x^2+1}{x^2+2}

For x=-1 => f(x)=1+11+2=23f(x) = \frac{1+1}{1+2}= \frac{2}{3}

For x=1 => f(x)=1+11+2=23f(x) = \frac{1+1}{1+2}= \frac{2}{3}

=> Not one-one function

=> Not a bijective (no inverse exists)


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