Question #234646

Find the complement of the following expression using dual of a function:

1. xy' + x'y

2. (AB' + C) D' + E

3. AB (C'D + CD') + A'B' (C' +D) (C + D')

4. (x + y+ z) (x' + z') (x + y)


1
Expert's answer
2021-09-10T10:08:55-0400

1.[xy+xy]=(xy).(xy)=(x+y).(x+y)=xy+xy1.[xy'+x'y]' = (xy')' . (x'y)' = (x'+y).(x+y') = xy + x'y'

2.[(AB+C)D+E]=[(AB+C)D].E=[(AB+C)+D].E=[(A+B).C+D].E=(A+B+D).(C+D).E2.[(AB'+C)D'+E]' = [(AB'+C)D']'.E' \\= [(AB'+C)'+D] . E'= [(A'+B).C' +D].E' \\ = (A'+B+D).(C'+D).E'

3.[AB(CD+CD)+AB(C+D)(C+D)]=(AB(CD+CD)).(AB(C+D)(C+D))=(A+B+CD+DC).(CD+CD+A+B)3. [AB (C'D + CD') + A'B' (C' +D) (C + D')]'\\=(AB (C'D + CD'))'.(A'B' (C' +D) (C + D'))' \\=(A+B+CD'+DC').(CD+C'D'+A'+B')

4.[(x+y+z)(x+z)(x+y)]=(x+y+z)+(x+z)+(x+y)=xyz+xz+xy4.[(x+y'+z)(x'+z')(x+y)]' = (x+y'+z)'+(x'+z')'+(x+y)'\\= x'yz' + xz + x'y



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