Find these terms of the sequence (An}, where An = 2(3)n + 5
Given the sequence An , the terms of the sequence can be found by substituting for values of n, where n=1,2,3,4,5,6,7,8, ... in the general term of that sequence.
Given An= 2(3)n + 5 the terms of this sequence are given by,
A1=2(3)1+5=6+5=11
A2=2(3)2+5=12+5=17
A3=2(3)3+5=18+5=23
A4=2(3)4+5=24+5=29
A5=2(3)5+5=30+5=35
A6=2(3)6+5=36+5=41
A7=2(3)7+5=42+5=47
A8=2(3)8+5=48+5=53
A9=2(3)9+5=54+5=59
A10=2(3)10+5=60+5=65
This procedure is continued until the desired number of terms of the sequence are found
Therefore, the first ten terms of this sequence are,
11,17, 23,29,35,41,47,53,59,65, ...
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