Let Q(x) be the statement “x + 1 > 2x.” If the domain consists of all integers, what are these truth values? a) Q(0) b) Q(−1) c) Q(1) d) ∃xQ(x) e) ∀xQ(x) f) ∃x¬Q(x) g) ∀x¬Q(x)
QUESTION
Let Q(x) be the statement “x + 1 > 2x.” If the domain consists of all integers, what are these truth values? a) Q(0) b) Q(−1) c) Q(1) d) ∃xQ(x) e) ∀xQ(x) f) ∃x¬Q(x) g) ∀x¬Q(x)
SOLUTION
a) Q(0) is true because;
put x = 0 in x + 1 > 2x
= 0 + 1 > 2 * 0
= 1 > 0
Answer: True
b) Q(-1) is true because;
if we put x = - 1 in x + 1 > 2x
= - 1 + 1 > 2 (-1)
= 0 > -2
Answer: True
c) Q(1) is false because;
if we put x = 1 in x + 1 > 2x
= 1 + 1 > 2 * 1
= 2 > 2
But this is not true
Answer: False
d) the statement is true because;
If we put x = 0 in x + 1 > 2x
= 0 + 1 > 2 * 0
= 1 > 0
Answer: True
e) The statement is false because;
When we put x = 1 then statement becomes false.
Answer: False
f) The statement is true because;
If x = 3
3 + 1 ≤ 2 * 3
= 4 ≤ 6
So the statement is true
Answer: True
g) The statement is false because
If we suppose x = 0 and x + 1 ≤ 2x
then,
0 + 1 ≤ 2 * 0
= 1 ≤ 0
Answer: False
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