Question #231602

find 200 sum k=100^k



1
Expert's answer
2021-09-01T07:34:02-0400
k=100200k=k=1200kk=199k\displaystyle\sum_{k=100}^{200}k=\displaystyle\sum_{k=1}^{200}k-\displaystyle\sum_{k=1}^{99}k

=200(200+1)299(99+1)2==\dfrac{200(200+1)}{2}-\dfrac{99(99+1)}{2}=

=50(40299)=15150=50(402-99)=15150


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