Question #231598

3a²n−1


1
Expert's answer
2021-09-01T10:53:01-0400

3a2n13a^2n−1

3a2n1=03a^2n-1=0

3a2n1+1=0+13a^2n-1+1=0+1

3a2n=13a^2n=1

3a2n3a2=13a2;a0\frac{3a^2n}{3a^2}=\frac{1}{3a^2};\:a\ne \:0

n=13a2;a0n=\frac{1}{3a^2};\:\:a\ne \:\:0


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