Answer to Question #231598 in Discrete Mathematics for shavneet

Question

3a²n−1

Answer 1

$3a^2n−1$

$3a^2n-1=0$

$3a^2n-1+1=0+1$

$3a^2n=1$

$\frac{3a^2n}{3a^2}=\frac{1}{3a^2};\:a\ne \:0$

$n=\frac{1}{3a^2};\:\:a\ne \:\:0$