Part 1 and 2
Part a
(2, 2), (2, 1),(1, 4), (1, 3), (1, 2), (1, 1)
Part b
(3, 2), (3, 3),(3, 4), (4, 1), (4, 2), (4, 3), (4, 4)
Part c
P(A)={∅,{a},{b},{c},{a,b},{b,c},{a,c},{a,b,c}}.
Let's show S=(P(A),⊆) is a poset. Let's show that S satisfies the following three properties.
- Reflexivity. For every x∈P(A) x⊆x is trivially true.
- Antisymmetry. Let x,y∈P(A) and x⊆y∧y⊆z.Then x=y from the definition.
- Transitivity. Let x,y,z∈P(A) and x⊆y∧y⊆x. Then for alla∈x we have a∈y, and therefore a∈z. Thus x⊆z.
The Hasse diagram for (P(A),⊆) is shown below.
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