Question 1.
Let . Describe if is the following relation:
1. is the relation on ;
2. is the relation on ;
3. is the relation on .
Solution.
(a) is the relation “to be strictly less than”, i. e. if and only if is strictly less that . We can even write all the pairs , which belong to :
However, for example, , because 1 equals 1 and hence it is not strictly less that 1.
(b) is the relation “to be greater than or equal to”, i. e. if and only if is strictly greater than or equal to . Equivalently, if and only if is not strictly less than . We see that this relation is the complement of the relation considered above. So,
(c) Recall that is the set of all subsets of , i. e.
The relation on is the relation “to be a proper subset”. This means that for all we have if and only if is a subset of , and there are elements of which do not belong to . For example, , because is contained in and does not coincide with the whole . But , because is not a subset of . Moreover, , because is a subset of , which is not proper. ∎