Question #22558

Let A={1,2,3}
a.) R is the relation < on A
b.) R is the relation >= on A
c. ) R is the relation ⊂ on Ƥ (A)

Expert's answer

Question 1.

Let A={1,2,3}A=\{1,2,3\}. Describe RR if RR is the following relation:

1. RR is the relation << on AA;

2. RR is the relation \geq on AA;

3. RR is the relation \subset on P(A)P(A).

Solution.

(a) RR is the relation “to be strictly less than”, i. e. (a,b)R(a,b)\in R if and only if aa is strictly less that bb. We can even write all the pairs (a,b)(a,b), which belong to RR:

R={(1,2),(1,3),(2,3)}.R=\{(1,2),(1,3),(2,3)\}.

However, for example, (1,1)∉R(1,1)\not\in R, because 1 equals 1 and hence it is not strictly less that 1.

(b) RR is the relation “to be greater than or equal to”, i. e. (a,b)R(a,b)\in R if and only if aa is strictly greater than or equal to bb. Equivalently, (a,b)R(a,b)\in R if and only if aa is not strictly less than bb. We see that this relation is the complement of the relation << considered above. So,

R={(1,1),(2,1),(2,2),(3,1),(3,2),(3,3)}.R=\{(1,1),(2,1),(2,2),(3,1),(3,2),(3,3)\}.

(c) Recall that P(A)P(A) is the set of all subsets of A={1,2,3}A=\{1,2,3\}, i. e.

P(A)={,{1},{2},{3},{1,2},{1,3},{2,3},{1,2,3}}.P(A)=\{\emptyset,\{1\},\{2\},\{3\},\{1,2\},\{1,3\},\{2,3\},\{1,2,3\}\}.

The relation \subset on P(A)P(A) is the relation “to be a proper subset”. This means that for all X,YP(A)X,Y\in P(A) we have XYX\subset Y if and only if XX is a subset of YY, and there are elements of YY which do not belong to XX. For example, {1}{1,3}\{1\}\subset\{1,3\}, because {1}\{1\} is contained in {1,3}\{1,3\} and does not coincide with the whole {1,3}\{1,3\}. But {1}⊄{2,3}\{1\}\not\subset\{2,3\}, because {1}\{1\} is not a subset of {2,3}\{2,3\}. Moreover, {1}⊄{1}\{1\}\not\subset\{1\}, because {1}\{1\} is a subset of {1}\{1\}, which is not proper. ∎

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