Let use a Karnaugh map to simplify the following Boolean expression:
(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)
A Karnaugh map is the following:

We conclude that this expression is equivalent to x′∧y′∧z′. It follows also from the idempotent law: p∨p=p.
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