Question #221675

Use a Karnaugh map to simplify the following Boolean expression:

(x'∧\land y'∧\land z') v (x'∧\land y'∧\land z') v (x'∧\land y'∧\land z') v (x'∧\land y'∧\land z') v (x'∧\land y'∧\land z')


Expert's answer

Let use a Karnaugh map to simplify the following Boolean expression:


(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)∨(x′∧y′∧z′)(x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z')


A Karnaugh map is the following:





We conclude that this expression is equivalent to x′∧y′∧z′.x'\land y'\land z'. It follows also from the idempotent law: p∨p=p.p\lor p=p.


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