Question #221675

Use a Karnaugh map to simplify the following Boolean expression:

(x'\land y'\land z') v (x'\land y'\land z') v (x'\land y'\land z') v (x'\land y'\land z') v (x'\land y'\land z')


1
Expert's answer
2021-08-03T07:02:38-0400

Let use a Karnaugh map to simplify the following Boolean expression:


(xyz)(xyz)(xyz)(xyz)(xyz)(x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z') \lor (x'\land y'\land z')


A Karnaugh map is the following:





We conclude that this expression is equivalent to xyz.x'\land y'\land z'. It follows also from the idempotent law: pp=p.p\lor p=p.


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