W∪Y={1,2,3,4,5,6,7,8,9}W\cup Y=\{1,2,3,4,5,6,7,8,9\}W∪Y={1,2,3,4,5,6,7,8,9}
Q∩Y={2,4,6,8}Q\cap Y=\{2,4,6,8\}Q∩Y={2,4,6,8}
Yc={3,7,10}Y^c=\{3,7,10\}Yc={3,7,10}.
So P∖Y=P∩Yc=P∩{3,7,10}P\setminus Y = P \cap Y^c=P\cap \{3,7,10\}P∖Y=P∩Yc=P∩{3,7,10}.
W∩Q={2,4,6,8}W\cap Q=\{2,4,6,8\}W∩Q={2,4,6,8}.
Hence (W∩Q)∪Y={1,2,4,5,6,8,9}=Y(W\cap Q)\cup Y=\{1,2,4,5,6,8,9\}=Y(W∩Q)∪Y={1,2,4,5,6,8,9}=Y
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