a) (p ↔ q) ⊕ (¬p ↔¬r)
b) (p → q) ∧ (¬p → r)
Solution.
a)
This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.
b)
This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.
Comments
Leave a comment