Answer to Question #212770 in Discrete Mathematics for dipayan

Question #212770

a)     (p ↔ q) ⊕ (¬p ↔¬r)

b)     (p → q) ∧ (¬p → r)



1
Expert's answer
2021-07-20T04:18:11-0400

Solution.

a)



This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.

b)



This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.


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