Question

a)     (p ↔ q) ⊕ (¬p ↔¬r)

b)     (p → q) ∧ (¬p → r)

Answer 1

Solution.

a)

This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.

b)

This formula is not a contradiction and is not a tautology because it takes different values for all possible values of p,q,r.