Question #211818

Suppose U = {1, 2, 3, 4, 5, a, b, c} is a universal set with the subset A = {a, b, c, 1, 2, 3, 4}.

Answer questions 1 and 2 by using the given sets U and A.


Question 1

Which one of the following relations on A is NOT functional?

1. {(1, 3), (b, 3), (1, 4), (b, 2), (c, 2)}

2. {(a, c), (b, c), (c, b), (1, 3), (2, 3), (3, a)}

3. {(a, a), (c, c), (2, 2), (3, 3), (4, 4)}

4. {(a, c), (b, c), (1, 3), (3, 3)}


Question 2

Which one of the following alternatives represents a surjective function from U to A?

1. {(1, 4), (2, b), (3, 3), (4, 3), (5, a), (a, c), (b, 1), (c, b)}

2. {(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)}

3. {(1, a), (2, c), (3, b), (4, 1), (a, c), (b, 2), (c, 3)}

4. {(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)}


1
Expert's answer
2021-07-16T14:33:28-0400

Question 1

A function is a relation in which each input has only one output.

In the relation {(1, 3), (b, 3), (1, 4), (b, 2), (c, 2)} the input x = 1 has multiple outputs: y = 3 and y = 4,

the input x = b has multiple outputs: y = 3 and y = 2.


1. {(1, 3), (b, 3), (1, 4), (b, 2), (c, 2)}


Question 2

1. Since 

range{(1,4),(2,b),(3,3),(4,3),(5,a),(a,c),(b,1),(c,b)}range \{(1, 4), (2, b), (3, 3), (4, 3), (5, a), (a, c), (b, 1), (c, b)\}




={4,b,3,a,c,1,b}A,=\{4,b,3,a,c,1,b\}\ne A,

we conclude that this function is not surjective.


2. Since 

range{(a,1),(b,2),(c,a),(1,4),(2,b),(3,3),(4,c)}range \{(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)\}

 

={1,2,a,4,b,3,c}=A,=\{1,2,a,4,b,3,c\}= A,

but 

domain{(a,1),(b,2),(c,a),(1,4),(2,b),(3,3),(4,c)}domain \{(a, 1), (b, 2), (c, a), (1, 4), (2, b), (3, 3), (4, c)\}

 

={a,b,c,1,2,3,4}U=\{a,b,c,1,2,3,4\}\ne U

we conclude that this is not a surjective function from UU to AA.


3. Since 


range{(1,a),(2,c),(3,b),(4,1),(a,c),(b,2),(c,3)}range \{(1, a), (2, c), (3, b), (4, 1), (a, c), (b, 2), (c, 3)\}

 

={a,c,b,1,2,3}A,=\{a,c,b,1,2,3\}\ne A,

we conclude that this function is not surjective.


4. Since 

range{(1,a),(2,b),(3,4),(4,3),(5,c),(a,a),(b,1),(c,2)}range \{(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)\}




={a,b,4,3,c,a,1,2}=A=\{a,b,4,3,c,a,1,2\}= A


and

domain{(1,a),(2,b),(3,4),(4,3),(5,c),(a,a),(b,1),(c,2)}domain \{(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)\}

 

={1,2,3,4,5,a,b,c}=U,=\{1,2,3,4,5,a,b,c\}=U,

we conclude that this function is surjective function from UU to AA .


4. {(1, a), (2, b), (3, 4), (4, 3), (5, c), (a, a), (b, 1), (c, 2)}



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