Answer to Question #209670 in Discrete Mathematics for Farhaan

Question

£(x - 50) =60,£(y-20) = -20,£(x -50)^2 = 450,£(y - 20)^2 = 200,£(x - 50)(y - 20) = -100

Answer 1

Solution:

£(x - 50) =60,

$\Rightarrow x=60+50=110$

£(y-20) = -20,

$\Rightarrow y=-20+20=0$

£(x -50)^2 = 450,

$\Rightarrow x=\pm\sqrt{450}+50=\pm15\sqrt{2}+50$

£(y - 20)^2 = 200,

$\Rightarrow y=\pm\sqrt{200}+20=\pm10\sqrt{2}+20$

£(x - 50)(y - 20) = -100

$\Rightarrow xy-50y-20y+1000=-100 \\\Rightarrow xy-50y-20y=-1100$