Question #20312

How do i solve this? Prove the following: if r and s are rational numbers then, r-s is rational

Expert's answer

Prove the following: if rr and ss are rational numbers then, rsr - s is rational

Proof.

Suppose rr and ss are rational numbers. [We must show that rsr - s is rational.] Then, by the definition of rational numbers, we have


r=ab for some integers a and b with b0.r = \frac{a}{b} \text{ for some integers } a \text{ and } b \text{ with } b \neq 0.s=cd for some integers c and d with d0.s = \frac{c}{d} \text{ for some integers } c \text{ and } d \text{ with } d \neq 0.rs=abcd=adbcbdr - s = \frac{a}{b} - \frac{c}{d} = \frac{ad - bc}{bd}


Now, let p=adbcp = ad - bc and q=bdq = bd. Then, pp and qq are integers [because products and sums(differences) of integers are integers and because a,b,ca, b, c and dd are all integers. Also, q0q \neq 0 by zero product property] Hence,


rs=pq, where p and q are integers and q0.r - s = \frac{p}{q}, \text{ where } p \text{ and } q \text{ are integers and } q \neq 0.


Therefore, by definition of a rational number, rsr - s is rational.

This is what was to be shown.


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