If P(k) = k2
(k + 2)(k – 1) is true, then what is P (k + 1)?
Solution:
P(k)=k2(k+2)(k−1)P(k)=k^2(k+2)(k-1)P(k)=k2(k+2)(k−1)
Now, replace kkk with (k+1)(k+1)(k+1),
P(k+1)=(k+1)2(k+1+2)(k+1−1)=(k2+1+2k)(k+3)(k)=k(k+3)(k2+2k+1)P(k+1)=(k+1)^2(k+1+2)(k+1-1) \\=(k^2+1+2k)(k+3)(k) \\=k(k+3)(k^2+2k+1)P(k+1)=(k+1)2(k+1+2)(k+1−1)=(k2+1+2k)(k+3)(k)=k(k+3)(k2+2k+1)
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