If the statement q ∧ r is true, determine all combinations of truth values for p and s such that the statement (q → [¬p ∨ s]) ∧ [¬s → r] is true.
If the statement "q \u2227 r" is true, then "q" is true and "r" is true. Since "(q \u2192 [\u00acp \u2228 s]) \u2227 [\u00acs \u2192 r]" is true, we conclude that "q \u2192 [\u00acp \u2228 s]" is true and "\u00acs \u2192 r" is also must be true. Taking into account that "q \u2192 [\u00acp \u2228 s]" is true and "q" is true, we conclude that "\u00acp \u2228 s" is also must be true. Since "r" is true, the implication "\u00acs \u2192 r" is true for any truth value of "s". Taking into account that "\u00acp \u2228 s" is false if and only if "p" is true and "s" is false, we conclude that "(q \u2192 [\u00acp \u2228 s]) \u2227 [\u00acs \u2192 r]" is true if and only if "p" is true and "s" is true or "p" is false and "s" is false or "p" is false and "s" is true.
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