Answer to Question #182338 in Discrete Mathematics for michael

Question

Here are some scenarios:

• According to market research, a business has a 75% chance of making money in the first 3 years
• According to lab testing, of a certain kind of experimental light bulb will work after 3 years.
• According to experts, the likelihood of a car needing major repairs in the first 3 years is 0.7.

a. Write the scenarios in order of likelihood from least to greatest after three years: the business makes money, the light bulb still works, and the car needs major repairs.

Answer 1

a.The correct order in terms of likelihood from least to greatest would be

 $P(\text{Car repair}) = 0.70 -> P(\text{Business}) = 0.75 -> P(\text{Light bulb}) = 0.83$  

Car needs major repairs -> Business makes money -> Light bulb still works 

Step-by-step explanation:

 We are given probabilities of three different events.

 According to market research, a business has a 75% chance of making money in the first 3 years. 

P(Business) = 75% = 0.75 

According to lab testing, 5/6 of a certain kind of experimental light bulb will work after 3 years.

 P(Light bulb) = 5/6 = 0.83 

According to experts, the likelihood of a car needing major repairs in the first 3 years is 0.7. 

P(Car repair) = 0.70 

We are asked to write these scenarios in order of likelihood from least to greatest after three years. 

Which means that the events with least probability is less likely to occur.

 The least probability is of car repair, then business and then light bulb.

 So the correct order in terms of likelihood from least to greatest would be 

P(Car repair) = 0.70 -> P(Business) = 0.75 -> P(Light bulb) = 0.83 

Car needs major repairs -> Business makes money -> Light bulb still work .