If R, S and T are relations over the set A, then: Prove that (S∩T)∘R= (S∘R)∩(T∘R).
Let x and y be the arbitary element belongs to set A,
"(x,y)\\in R,S,T"
"(x,y)\\in(S\\cap T)oR"
"\u21d2x\\in (So R)\\cap(ToR) (\\text{ As It follows Distributive law})"
"\\Rightarrow (S\\cap R)oR=(SoR)\\cap(ToR)" ,hence proved.
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