If R, S and T are relations over the set A, then: Prove that If R⊆S, then T∘R ⊆ T∘S and R∘T ⊆ S∘T
Let "(a,b)\\in T\\circ R". Then there exists "x\\in A" such that "(a,x)\\in T" and "(x,b)\\in R". Since "R\u2286S", we conclude that "(x,b)\\in S", and therefore, "(a,b)\\in T\\circ S." Consequently, "T\\circ R\u2286T\\circ S."
Let "(a,b)\\in R\\circ T". Then there exists "x\\in A" such that "(a,x)\\in R" and "(x,b)\\in T". Since "R\u2286S", we conclude that "(a,x)\\in S", and therefore, "(a,b)\\in S\\circ T." Consequently, "R\\circ T\u2286S\\circ T."
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