Let (a,b)∈T∘R. Then there exists x∈A such that (a,x)∈T and (x,b)∈R. Since R⊆S, we conclude that (x,b)∈S, and therefore, (a,b)∈T∘S. Consequently, T∘R⊆T∘S.
Let (a,b)∈R∘T. Then there exists x∈A such that (a,x)∈R and (x,b)∈T. Since R⊆S, we conclude that (a,x)∈S, and therefore, (a,b)∈S∘T. Consequently, R∘T⊆S∘T.
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