~(~p^q) ^(pvq) =p
"\\neg(\\neg p \\wedge q)\\wedge (p \\vee q)=\\\\\n(p \\vee \\neg q) \\wedge (p \\vee q)\\{De Morgan's\\}=\\\\\np \\wedge (\\neg q \\vee q)\\{Distributive\\}=\\\\\np \\wedge 1 \\{ Identity\\}=\\\\\np"
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