Answer to Question #171796 in Discrete Mathematics for AMIT RAWAT

Discrete Mathematics

Question #171796

In how many ways can six boys and four girls be arranged in a straight line so that no two girls are ever together.

Expert's answer

$С^7_4×6!×4! =\frac{7!×6!×4!}{4!×3!}=7\cdot6\cdot5\cdot4\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1=604800$

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